I am currently trying to troubleshoot a customer’s Simplex 4010 that is displaying “PIV Sprinkler Monitor TROUBLE M1-67”.
Obviously I am somewhat smart enough to know this is an issue with an open circuit. I started with the PIV tamper switch. When activated, I received continuity across the Comm and N.O. leads, so its not the switch. I then removed the black and red wire from the tamper, touched them together, and did NOT get a Supervisory at the FACP. So, naturally, I found the module.
The module setup is as follow: SLC comes into a 4090-9001 module, then daisy chains to the neighboring tamper module (for the OS&Y). The PIV module’s other terminals then go out to the PIV and OS&Y to the OS&Y.
We replacement the module, set the dip switches correctly, but still nothing (trouble signal). We even tried strapping out the new module at the initialing device terminals (6.8k) and it worked (system normal) at first, but it came back into trouble when we tried to hook the tamper up again AND the new module would not clear even after we strapped it out again, just like the first time. We put the OLD module back in, strapped it out in the same place (terminals of module), AND IT CLEARED!
Keep in mind, that daisy chained OS&Y module works perfectly, even though it’s AFTER the PIV in terms of SLC direction.
It sounds like an end of line issue. But you said you saw 6.8K when you metered the wires coming from the tamper switch?
I’m not familiar with the term “strapping out” is that similar to what we would call “splicing through” to basically complete the circuit after removing a questionable device?
The module needs to see the 6.8K resistor all the time. If not the system will show Trouble. The EOl should be in parallel with the normally open cantacts on the post valve tamper switch. (valve in open position). When the valve is closed, the tamper switch contacts close and the module sees that as an alarm. Make sure the small wires on the resistor are secure under the tamper switch screws.
I know that, but even with the resistor at the brand new module and the tamper wires bypassed, it was system normal for a few minutes, THEN changed to trouble once we tried it again. Also, with everything hooked up “normally” (wires to tamper, tamper with EOLR), we are not getting ANY voltage at the tamper. The tamper switch mechanism works and was tested via continuity tester.
The trouble was also intermittent for a week or so. Could this be an underground wire from the module to the tamper issue?
By “strapping out”, I mean placing a resistor on the module where the initiating device terminals are. Essentially removing the tamper from the equation.
The weird part is, this brand new module worked temporarily in this “strapped out” configuration, then when trying to introduce the tamper wire, still a trouble with no voltage at the tamper switch. Wire goes about 20ft from the module, then underground to the tamper.
We then removed the tamper wires and tried to strap out the new module AGAIN, and nothing. Then, we put the old module back in, strap it out with a resistor, and it’s normal!
With the input wiring disconnected, the module should have voltage on the mapnet terminals and the circuit terminals with or without the resistor. If you don’t have both of those, either the module is bad or the mapnet is.
With the tamper circuit wires off of the module, but still connected to the tamper switch, measure resistance between a good earth ground and each circuit wire going outside. You should read infinity. No connection whatsoever between ground and either one of those wires.
There should not be voltage on the load side of the module. (at the tamper switch.) That’s a dry contact, with 6.8k ohms at the tamper. So if you were to remove the wires from the module and meter them there, you should read 0v and 6.8k ohms. If you don’t have 6.8k then there is an open on one of the wires between the module and the resistor.
There has to be some voltage on the output terminals in order to “see” the eol resistor. A relay module would have no power, but a monitor module needs voltage and current to operate.